(-x^2)-(-x^2)=(-2x^2)

Solution for (-x^2)-(-x^2)=(-2x^2) equation:

(-x^2)-(-x^2)=(-2x^2)

We move all terms to the left:

(-x^2)-(-x^2)-((-2x^2))=0

We get rid of parentheses

-x^2+x^2-((-2x^2))=0


We calculate terms in parentheses: -((-2x^2)), so:

(-2x^2)

We get rid of parentheses

-2x^2

Back to the equation:

-(-2x^2)


We add all the numbers together, and all the variables

-(-2x^2)=0

We get rid of parentheses

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$